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by simonask 19 days ago
Panics in Rust do not currently time-travel like that (including panics from failed bounds checks), and that's a good thing. The reason is that panicking does not imply terminating the process - they can be caught and handled, just like exceptions in C++. In fact, they use the same stack unwinding mechanism by default.

What the compiler is allowed to do is to shorten the loop by one and unconditionally panic after the loop, but this falls under the purview of the LLVM optimizer.

2 comments

It's true that panics (unlike UB) cannot automatically time-travel, but your justification is weak. Recovering from panics can only prevent this optimization if the loop have side effects, and LLVM knows when panic=abort is set.
The post-panic situation is a problem in Rust. After a panic, you're in a somewhat abnormal state. Rust panics are not supposed to be a catchable exception system. If something other than program termination is in the near future, that's a problem.

That does create a problem for early panics, panicking when panic becomes inevitable but has not happened yet. This deserves more thought.

I mean, sure, dead code elimination applies to all optimized code. The important thing to understand is that panicking in Rust does not get magic treatment by the Rust compiler. It’s just a function that is declared in the type system to never return.
Once it shortens the loop, the compiler can also observe that `tab` is a local variable and therefore move the writes up "to the initializer." It can then see that the variable is unused and delete it, and also delete the loop.