| > At some point you get what APL is all about, and you can move on with life without too many regrets. Unfortunately, this seems to be a common experience. A lot of smart people only engage with APL via toy puzzles, like you did, and bounce off because that gives no insight about how to use the language in real life. IME, to really start getting APL you need to write and rewrite a full application 20 times. It helps to read code from the masters, too [0, 1, 2, 3, 4]. These all approach architecture in different ways: pedagogical FP style, OOP heavy, data-oriented design, event-driven state-machine, or a mix of the above. [0]:https://dfns.dyalog.com/ [1]:https://github.com/Co-dfns/MicroUI-APL [2]:https://github.com/Dyalog/ewc [3]:https://github.com/Co-dfns/Co-dfns [4]:https://github.com/Dyalog/Jarvis/blob/master/Source/Jarvis.d... > As you can see, the famous prime generator is not even the Eratostenes' sieve, but a simple N^2 divisor counting computation. Well, that's because you wrote a divisor function, not a seive. Arguably, the ease of typing an outer product (i.e ∘.|⍨⍳N) can tempt us into writing quadratic algorithms unnecessarily, but this is just an experience issue, IMO. If we want a seive, we can just write one directly: p⊣{ω~n×1+⍳⌊N÷p⍪←n←ω↑⍨1⌊≢ω}⍣≡1↓1+⍳N⊣p←⍬
The algorithm is O(N log log N) as expected of a naive Eratosthenes implementation. You'll need ⎕IO←0 if you want to try it out.There's also a faster seive by Roger Hui [0] in the dfns workspace as well as a family of prime number functions [1] for things more than just prime generation. [0]:https://dfns.dyalog.com/n_sieve.htm [1]:https://dfns.dyalog.com/n_pco.htm |
The algorithm iterates over numbers ⍺ from 2 to N, removing the multiples that are greater than ⍺ and no greater than N from p. If the removal with ~ has to inspect all of p, then all the primes are there so we have asymptotically at least N/log N entries by the prime number theorem and we get N^2/log N time (when ⍺ is over N/2, no multiples are in range so this can be skipped, but that just cuts a constant factor 2 from the time). Conceivably p could be marked sorted, so the entries to remove could be found with a binary search. This is a bit harder to analyze, but I think each prime under √N will cause the list to change, and incur N/log N data movement. So you get at least (N/log N)^(3/2) cost, still quite a bit worse than linear.
Edit: changed the algorithm while I was writing... the new one is better, it keeps one list p of primes and one list ω of not-yet-marked-out numbers. However, primes are removed from ω one at a time, so that each of the N/log N primes has to be moved for each one before it, giving at least (N/log N)^2 cost (I mean, maybe an interpreter could binary search and also recognize when ~ only drops the first entry and do that by slicing? But the (N/log N)^(3/2) from above definitely holds). Mutating a bit array in place is pretty important to classical sieve performance.