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by tyg13 25 days ago
I see what you're going for, but I don't see how your example is UB. If `p` is a pointer, and, after your `if (p)` check, `p` is dereferenced unconditionally, then yes, your check for `p == NULL` could be removed, and the code under the `if` would be removed as well. But the example you've constructed is not UB.
1 comments

You misunderstood their example, I think.

If doesn't matter what 'p' is in their example. The point is: if 'f' is undefined behavior (rather than just impl-defined), then the optimizer concludes that the "if p { f() }" can never happen... which means that we're allowed to assume that 'if p { ... } else { ... }' (in the first part of the example) will always take the else branch. The compiler will optimize accordingly and just always call g() unconditionally.