|
|
|
|
|
by syncsynchalt
43 days ago
|
|
> If we pipe seq to less and look at the list of running processes using ps aux, we can see that the seq program is not running. ... This explains why the seq program is killed when it is piped to less. This explanation isn't correct, since a running `less` would not close the pipe and is still a reader. Writes to the pipe would block until `less` fully consumed it, or until `less` was quit such as with the `q` command. The text _is_ correct if you add a missing step to `q`uit out of the `less` program. I think this step must have been dropped along the way. Unfortunately the screen capture doesn't show this step either. |
|
The description of `seq` isn't even correct: "If a second argument is provided, the numbers will stop printing at the once the second number has been reached. Otherwise, the numbers will continue forever"
Nope, `seq`'s arguments are defined as `[first [incr]] last`. With a single argument, it counts up from 1 to `last`. Maybe some previous version of `seq` behaved differently, but not as far as I can recall.
But again, can't hold anything against the page given the disclaimer.