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by Kirby64 52 days ago
Plenty of USB-C cables are capable of charging at 5 amps continuously and do so today. How is the voltage relevant to how much power is dissipated in the cable? That’s the only difference between a 100W charger and a 240W charger.
1 comments
ProllyInfamous 50 days ago
>How is the voltage relevant

I'm envisioning some future frayedAF school laptop cord, where an increasing voltage correlates to higher likelihood that those amps can more-readily arc/jump (across melt, muck, and matter).

At the end of the day, an increase of either voltage and/or amps calls for a sturdier design (of ports and cables).

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Kirby64 50 days ago
> At the end of the day, an increase of either voltage and/or amps calls for a sturdier design (of ports and cables).

The cables themselves are already plenty tolerant from an insulation standpoint for 48V. Voltage is low enough to not harm anyone. The ports, as already mentioned elsewhere, are designed to have snubber circuits for rapid reduction in voltage during an unplug. There's a keep-alive to cut voltage as soon as it doesn't detect things plugged in anymore (or, perhaps, the cable gets damaged and can't communicate).

Seems to me like the sturdier design is already accounted for. I don't think "it's small therefore I don't like it" is a valid reason to distrust the standard inherently.

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ProllyInfamous 49 days ago
>I don't think "it's small therefore I don't like it" is a valid reason to distrust the standard inherently.

Thanks for writing this; it's where I fundamentally disagree, but appreciate your perspective. IMHO that's exactly the problem.

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