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by fch42
63 days ago
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xor'ing the elements of lists together also allows a test of "unordered equality" because 1^2^3^4^5 == (xor of any permutation of [1,2,3,4,5]). Yes there are false positives, and the false negative of all-zero/all-equal, but the test can be useful in a "bloom filter" type case. Have used it in dynamic firewalling rules ... one can do something pretty close to a JA3/JA4 TLS fingerprint in eBPF with that (to match the cipher lists). |
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