[jamie_ca]

Give two players cards, "Check" and "Checkmate".

Both players choose a card. Players then in turns reveal their card, and if Check, make another choice. The player first revealing Checkmate wins if their opponent's currently-chosen card is also a Checkmate.

[stavros]

But then this just gives the win to the first person to open their card, since in that round they had both selected Checkmate. Or, you have an incentive to rush to open your card when you know you've selected Checkmate, as you want to be the first one to open.

[jamie_ca]

Maybe I should've worded differently for clarity, the game doesn't go forever:

The player first revealing Checkmate ends the game. They win if their opponent's currently-chosen card is also a Checkmate, otherwise the opponent wins.

[manwe150]

In the proposed game above, there is no rounds, just alternating plays, in which you have to select you play before the other player announces their play, then swap and repeat

[stavros]

So both players select their cards, then player 1 announces, then player 2, then select, then player 2 announces, then player 1? This seems a bit limiting, as you can't really select Checkmate on the play where you don't reveal first, because you only stand to lose.

[smrq]

I believe the intended turn order is:

1: P1 selects 2: P2 selects 3: P1 reveals 4: P1 selects 5: P2 reveals 6: GOTO 2

I.e. each player always selects immediately before their opponent reveals.

[BoiledCabbage]

Yeah, but what stops P1 from DDos'ing and picking checkmate each time?

If P2 picks check the first time, then they're done. At any point after if they pick checkmate, since P1 has checkmate selected they will reveal it and P2 will lose.

It seems like a poorly thought through game...

[manwe150]

Because P1 lost on their first turn if P2 wasn’t about to pick checkmate

[stavros]

But then you won't know if the other player has selected checkmate when you reveal yours.