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by in-silico
72 days ago
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Model-free RL doesn't mean you aren't training a model. It means that you aren't explicitly building a model of the environment's f(s,a)=(s',r) transition function, which methods like Dreamer do. Q-learning only approximates the Q-value function, not the full state transition, so it is model-free. |
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Do you seriously think a writer of that post would think model-free RL means "not training a model at all"?
> Dreamer
Especially when I later mentioned dreamer myself specifically as a model-based algorithm
> Site guidelines: Please respond to the strongest plausible interpretation of what someone says