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by mesuvash
81 days ago
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IIUC, The paper's notation S^(d-1) means the unit sphere in R^d (e.g., the familiar unit circle is S^1 living in R^2). So, i think, x in the algorithm is already a unit vector. Reference:
Section 2:Preliminaries
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We use the notation S^d−1 to denote the hypersphere in R^d of radius 1. Section 3.1
Let x ∈ S^d−1 be a (worst-case) vector on the unit sphere in dimension d. |
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I was primarily aiming to confirm my understanding given the author's omission but also the scalar is subtly different than in your linked explanation (although conceptually equivalent).