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by amelius 86 days ago
That model doesn't explain the relatively sharp drop in the beginning.
5 comments

It absolutely does. The model that came closest simply used that model twice in the same equation. One for the cup and one for the air.
It does? There is a fast drop followed by a long decay, exponential in fact. The cooling rate is proportional to the temperature difference, so the drop is sharpest at the very beginning when the object is hottest.
I mean that initial drop doesn't look like it is part of the same exponential decay.
https://teatrade.co.uk/learning/physics-of-teh-tarik-foam.ht...

Apparently the act of pouring has a huge effect on temperature because of the surface area :: volume ratio of the fluid as it streams (and turbulence after striking the bottom). The site above claims a single pour can drop it 20-30 degrees. There may be a similar effect here.

Are you sure? I believe Newtown's law of cooling says the temperature will drop sharply at the beginning:

dT/dt = -k(T_0 - T_room)

so T(t) = T_room + (T_0 - T_room) exp(-kt)

exp(-x) has a fast drop off then levels off.

Ha. My university professor used this in a lab to catch people who slack off.

There is another factor here: convection. Its speed depends on the viscosity of the fluid and the temperature difference both. And viscosity itself depends on the temperature, so you get this very sharp dropoff.

https://www.electronics-tutorials.ws/rc/time-constant.html

scroll down, these graphs just don't look similar.

probably dominated by the cup as the ambient temperature initially and then as air/the counter top as the ambient temperature on the longer time scale, once the cup and the liquid near equilibrium