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by emih
82 days ago
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You can still do this though: let result = (barbalyze(c, d, $) . foobinade(a, b, $)) input
Or if you prefer left-to-right: let result = input
|> foobinade(a, b, $)
|> barbalyze(c, d, $)
Maybe what isn't clear is that this hole operator would bind to the innermost function call, not the whole statement. |
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