How heavy on tokens is this? I don't use these style workflows and am fairly new to claude code, so I assume it's better than 3x tokens when doing 3 passes?
It's not 3x because of 3 runs; can be more token, can be less.
The way of thinking it is, telling Claude to tackle the problem 3 times, each time it may or may not use different approach, fix or improve on things it did previously.
That's right. However if you use the v3 operator, you get three parallel versions being built, and then combined depending on which resolver you use (pick, merge, and compare).
The way of thinking it is, telling Claude to tackle the problem 3 times, each time it may or may not use different approach, fix or improve on things it did previously.