[cherryteastain]

OOP has nothing to do with it. In your C++ example, foo(bar const&); is basically the same as bar.foo();. At the end of the day, whether passing it in as an argument or accessing this via the method call syntax it's just a pointer to a struct. Not to mention, a C++ compiler can, and often does, choose to put even references to member variables in registers and access them that way within the method call.

This is a Python specific problem caused by everything being boxed by default and the interpreter does not even know what's in the box until it dereferences it, which is a problem that extends to the "self" object. In contrast in C++ the compiler knows everything there's to know about the type of this which avoids the issue.

[adrian17]

That's not true. I mean: it's true that it has little to do with OOP, but most imperative languages (only exception I know is Rust) have the issue, it's not "Python specific". For example (https://godbolt.org/z/aobz9q7Y9):

struct S { const int x; int f() const; }; int S::f() const { int a = x; printf("hello\n"); int b = x; return a-b; }

The compiler can't reuse 'x' unless it's able to prove that it definitely couldn't have changed during the `printf()` call - and it's unable to prove it. The member is loaded twice. C++ compilers can usually only prove it for trivial code with completely inlined functions that doesn't mutate any external state, or mutates in a definitely-not-aliasing way (strict aliasing). (and the `const` don't do any difference here at all)

In Python the difference is that it can basically never prove it at all.

[josefx]

> This is a Python specific problem caused by everything being boxed

I would say it is part python being highly dynamic and part C++ being full of undefined behavior.

A c++ compiler will only optimize member access if it can prove that the member isn't overwritten in the same thread. Compatible pointers, opaque method calls, ... the list of reasons why that optimization can fail is near endless, C even added the restrict keyword because just having write access to two pointers of compatible types can force the compiler to reload values constantly. In python anything is a function call to some unknown code and any function could get access to any variable on the stack (manipulating python stack frames is fun).

Then there is the fun thing the C++ compiler gets up to with varibles that are modified by different threads, while(!done) turning into while(true) because you didn't tell the compiler that done needs to be threadsafe is always fun.

[1718627440]

What is going on here is not, that an attribute might be changed concurrently and the interpreter can't optimize the access. That is also a consideration. But the major issue is that an attribute doesn't really refer to a single thing at all, but instead means whatever object is returned by a function call that implements a string lookup. __getattr__ is not an implementation detail of the language, but something that an object can implement how it wants to, just like __len__ or __gt__. It's part of the object behaviour, not part of the static interface. This is a fundamental design goal of the Python language.

[1718627440]

> This is a Python specific problem caused by everything being boxed by default and the interpreter does not even know what's in the box until it dereferences it

That's not the whole thing, what is going on. Every attribute access is a function call to __getattr__, that can return whatever object it wants.

bar.foo (...) is actually bar.__getattr__ ('foo') (bar, ...)

This dynamism is what makes Python Python and it allows you to wrap domain state in interface structure.