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by shawn_w 162 days ago
You're not using `integer` in the perl example like you're supposed to. Try

    perl -Minteger -E 'say ~-0'
and it should work as expected.
1 comments

That is true, but for the kind of code where I might use this trick, there usually aren't enough `~-$x` for `use integer;` to be worthwhile, I would just do `($x-1)` instead.