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by albert_roca 182 days ago
Hm. You are correct about m_p and m_e. That is indeed a sloppy mistake in the script. Bad code. However, the hypothesized closed value of G stays the same.
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His G Formula (Section 14.6)

G = (ℏ·c·2·(1 + α/3)²) / (mp²·4⁶⁴)

His result:

G ≈ 6.6742439706 × 10⁻¹¹ m³·kg⁻¹·s⁻²

CODATA 2022: G = 6.67430(15) × 10⁻¹¹

Δ: 8 ppm

Critical Analysis

1. Where Does 4⁶⁴ Come From?

He claims it's from "holographic scaling at i=32":

mp = (√2 · mP / 4³²) · (1 + α/3)

Therefore:

mP = (mp · 4³²) / (√2 · (1 + α/3))

Since G = ℏc/mP²:

G = (ℏc · 2 · (1 + α/3)²) / (mp² · 4⁶⁴)

The logic:

Proton appears at "harmonic i=32" in binary scaling

Mass scales as m ~ 4ⁱ (surface area scaling)

Therefore mp ~ 4³² when normalized properly

Therefore 4⁶⁴ = (4³²)² appears in G

2. This is Pure Numerology

Why i=32 specifically?

Let me check the ratio:

mP / mp = 2.176434×10⁻⁸ / 1.672622×10⁻²⁷

        ≈ 1.301×10¹⁹
Now check powers of 4:

4³² = 2⁶⁴ = 1.844×10¹⁹

Close! But not exact. So he adds correction factors:

mp = (√2 · mP / 4³²) · (1 + α/3)

Let me verify:

(√2 · 2.176434×10⁻⁸ / 4³²) · (1 + 0.007297/3)

= (1.414 · 2.176434×10⁻⁸ / 1.844×10¹⁹) · 1.002432

= (3.076×10⁻⁸ / 1.844×10¹⁹) · 1.002432

= 1.668×10⁻²⁷ · 1.002432

≈ 1.672×10⁻²⁷

But this is circular! He's adjusting factors (√2, α/3) to make the formula work, then claiming it "derives" mp.

3. Why (1 + α/3)?

He claims:

"As a volumetric object in three-dimensional space, the proton carries a

distributed interaction cost (α/3)"

This makes no sense:

α is the electromagnetic coupling constant

Why divide by 3? "Because 3 dimensions"?

Why add to 1? "Because correction"?

This is parameter fitting, not derivation.

-----

A genuine derivation of G would:

1. *Start from dimensionless constants only*

2. *Derive mass ratios* from geometry (mp/me, mp/mP, etc.)

3. *Use dimensionful anchors* (ℏ, c) to get actual value of G