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by dzaima
190 days ago
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Storing the data in nodes doesn't work if the given structure may need to be in multiple linked lists, which iirc was a concern for the kernel? And generally I'd imagine it's quite a weird form for data structures for which being in a linked list isn't a core aspect (no clue what specifically the kernel uses, but I could imagine situations where where objects aren't in any linked list for 99% of time, but must be able to be chained in even if there are 0 bytes of free RAM ("Error: cannot free memory because memory is full" is probably not a thing you'd ever want to see)). |
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That's a great point! A language almost like C plus a smart enough compiler could do the unboxing, but this technique doesn't work for multiple structures.
> And generally I'd imagine it's quite a weird form for data structures for which being in a linked list isn't a core aspect (no clue what specifically the kernel uses, but I could imagine situations where where objects aren't in any linked list for 99% of time, but must be able to be chained in even if there are 0 bytes of free RAM ("Error: cannot free memory because memory is full" is probably not a thing you'd ever want to see)).
I think you are right in practice, though in principle you could pre-allocate the necessary memory when you create the items? When you have the intrusive links, you pay for their allocation already anyway, too. In terms of total storage space, you wouldn't pay for more.
(And you don't have to formally alloc them via a call to kmalloc or so. In the sense that you don't need to find a space for them: you just need to make sure that the system keeps a big enough buffer of contiguous-enough space somewhere. Similar to how many filesystems allow you to reserve space for root, but that doesn't mean any particular block is reserved for root up-front.)
But as I thought, that's about in-principle memory usage. A language like C makes the alternative of intrusive data structures much simpler.