While it's very legitimate question, the answer is between the lines in the README, and it mostly means that there is a user space binary compatibility for everything that is implemented.
It might seem obscure, but syscalls to get access to kernel requires a tight integration on compilation and linking. So this is their approach and this is where the compatibility really means something : since you can cross compile on another machine, they don't need the full toolchain right away. Just compile your code on a linux machine, and run it there. You're at the mercy of all missing kernel API implementations, but it looks like a very good strategy if you aim is to code a kernel, as you only have to focus on actual syscalls implementation without getting distracted by toolchain.
It might seem obscure, but syscalls to get access to kernel requires a tight integration on compilation and linking. So this is their approach and this is where the compatibility really means something : since you can cross compile on another machine, they don't need the full toolchain right away. Just compile your code on a linux machine, and run it there. You're at the mercy of all missing kernel API implementations, but it looks like a very good strategy if you aim is to code a kernel, as you only have to focus on actual syscalls implementation without getting distracted by toolchain.