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by Bratmon 214 days ago
So then wouldn't that make $|++ the variable name?
1 comments

Smokey, this is not 'Nam! This is <Perl>, there are rules!

'$' guarantees a scalar. Then it either alphanumeric id, or a single non-alphanumeric symbol. And the latter means you deal with a 'special' var which with 100% certainty has a documentation entry.