[weinzierl]

OMG, how did you remember that

  nabla x nabla = labla(ce)?

[henearkr]

I think you meant Laplace (Laplacian operator).

[weinzierl]

That's the mnemonic I was taught, but granted, it takes some artistic license to make it rhyme.

[henearkr]

Ha! lol ^^ Ok, I see!