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by morcus
220 days ago
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I just tried this, and I couldn't quite get it to work. ```
type PickType<B extends Boolean> = B extends true ? number ? string; function foo<T extends Boolean>(t: T): PickType<T> {
return t ? 42 : "42;
}
``` The compiler doesn't seem to get that the type of T is narrowed in the ternary branches, and thus Pick<T> is determined. The error I get is that a number isn't assignable to a Pick<T>. |
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