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by dgrunwald 217 days ago
If you need `0..=n`, you can't write `0..(n+1)` because that addition might overflow.
1 comments

I'm actually curious now how this is stored on `Range` in rust. I've certainly used ..= for exactly the reason you say, but as far as I'm aware `.end` on the range is the exclusive upper bound in all cases. What happens to `.end` in the overflowing case?

Edit: it doesn't use Range for ..=, but rather RangeInclusive, which works fine.