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by judofyr 248 days ago
Maybe I explained it a bit imprecise. I was trying to explain the following behavior:

    def foo
      p 1
      yield
      p 2
    end

    foo { break }
This only prints "1" because the break stops the execution of the invoked method (foo).
1 comments

WAT? I'm a 12+ years Ruby developer and I didn't know this.