If C = D^2, and you double compute, then 2C ==> 2D^2. How do you and the original author get 1.41D from 2D^2?
In other words, the required amount of data scales with the square root of the compute. The square root of 2 ~= 1.414. If you double the compute, you need roughly 1.414 times more data.
In other words, the required amount of data scales with the square root of the compute. The square root of 2 ~= 1.414. If you double the compute, you need roughly 1.414 times more data.