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by zissou
5023 days ago
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Did somebody say B = (X'X)^(-1)X'Y? Here is one of my favorite OLS-related abuses of linear algebra:
y = XB + e ---> e = y - XB ---> e = y - X(X'X)^(-1)X'Y ---> e = [I - X(X'X)^(-1)X'Y]y = My Now use the two idempotent matrices to compute the SSR:
e'e = (My)'(My) ---> e'e = y'M'My ---> e'e = y'MMy ---> e'e = y'My |
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