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by pontus
300 days ago
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Just to pile on here, there's also ambiguity around how the observed girl is selected. Consider the following framing: I go to a random house on a random street and knock on the door. A young girl opens the door. I ask how many siblings they have and they say one. What's the probability that they have a sister? Now it's 50% even though cosmetically it seems like it'd be fair to say that the family has at least one daughter. The reason is that once I see a girl at the door, I'm slightly more confident in that it's a GG household since a GB or BG household would sometimes show a boy opening the door (assuming the two kids are equally likely to open the door). P(GG | G at door) = P(G at door | GG) P(GG) / P(G at door) P(G at door) = 1/2 (by symmetry) So,
P(GG | G at door) = 1 * 1/4 * 2 = 1/2 |
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However, if the question is interpreted as "what's the probability of having two girls if we know there aren't two boys," then the event space is GB, BG, GG, and p(GG)/(p(GB) + p(BG) + p(GG)) = 1/3. Both GB and BG are in the event space because we are not conditioning on the sex of one specific child.