[torstenvl]

> It can't if arbitrary code (for example inside bar()) can forge pointers to that memory location.

Yes. It absolutely can. What are you even talking about?

C is not the Windows Start Menu. This habit of thinking it needs to do what it thinks I might expect instead of what I told it is deeply psychotic.

[gpderetta]

I litterally have no idea what are you trying to say. Do you mean that bar should be allowed to access *ptr with impunity or not?

[torstenvl]

I'm not trying to say anything. I said and meant exactly what I said. No more, no less. Your logic is obviously flawed. There is nothing preventing that optimization in the presence of a forged pointer in bar().

[gpderetta]

Either there is no provenance, forging is allowed and the optimization is disallowed; or there is provenance and forging the pointer and attempting to inspect (or modify) the value of *ptr in bar() is UB.

[ncruces]

You never converted ptr to an integer. If you did, if the pointer escapes, yes, I claim that then the allocation can't be optimized away. Why is that so bad?

[torstenvl]

Attempting to inspect or modify the value of *ptr in bar() through a forged pointer was always UB. You are saying absolutely nothing meaningful.