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by trealira
337 days ago
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> since haskell is non-strict, if can be implemented as a function, and iirc it is "If" can be implemented as a function in Haskell, but it's not a function. You can't pass it as a higher-order function and it uses the "then" and "else" keywords, too. But you could implement it as a function if you wanted: if' :: Bool -> a -> a
if' True x _ = x
if' False _ y = y
Then instead of writing something like this: max x y = if x > y then x else y
You'd write this: max x y = if' (x > y) x y
But the "then" and "else" remove the need for parentheses around the expressions. |
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