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by sureglymop 340 days ago
How so? If you specify the type int how would that save you from an overflow/underflow at runtime?
1 comments
alternatex 339 days ago
Not sure if types are supposed to protect against overflow/underflow, it's more in the arithmetic territory. Interesting idea though, I wonder if some programming language allows overflow/underflow checks directly in the types.
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Joker_vD 336 days ago
Yes, it's actually quite easy:

    +: (int<N>, int<N>) -> int<N+1>    // or (int<N>, bit) as the return type
    *: (int<N>, int<N>) -> int<2*N>
etc. Those are the actual types of those arithmetic operations.
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