| "Functions Are Vectors"? Let's see: Let A be a non-empty set, N
the set of positive whole numbers, and X
the set of all functions f f: A --> N with usual notation. Assume as is common, the scalars are the
set of real numbers, but the set of complex
numbers will also do. So, is X a vector space and, thus, each
f in X a vector? No, since -f is not in X. Neither is
(1/2)f. Some references (with TeX markup): Paul R.\ Halmos,
{\it Finite-Dimensional Vector Spaces, Second Edition\/} linear algebra treated as functional analysis. Walter Rudin,
{\it Real and Complex Analysis\/} with Lebesgue integration and, then,
Banach and Hilbert vector spaces. Walter Rudin,
{\it Functional Analysis\/} with Fourier theory. Jacques Neveu,
{\it Mathematical Foundations of the Calculus of Probability\/} with random variables, that is,
functions from a probability space to,
usually, the set of real numbers with
convergence results, building on the
work A. Kolmogorov building on the work of
H. Lebesgue. |
This is what the article is very explicitly about. I guess you can quibble that the title is imprecise, but it's just a title and the article makes it clear.