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by gizmo686
342 days ago
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It is not required for vector spaces to have a basis. As it turns out, the claim that every vector space has a basis is equivalent to the axiom of choice, which seems well beyond the scope of the article. However, the particular vector space in question (functions from R to R) does have a basis, which the author describes. That basis is not as useful as a basis typically is for finite dimensional (or even countably unfitine dimensional) vector spaces, but it still exists. |
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> However, the particular vector space in question (functions from R to R) does have a basis, which the author describes.
No, there is no known constructible basis for R -> R functions.