[Hercuros]

I guess the internal exposure state would be “wrong” if the compiler removes the dead load (e.g in a pass that runs before provenance analysis).

However, if all of the program paths from that point onward behave the same as if the pointer was marked as exposed, that would be fine. It’s only “wrong” to track the incorrect abstract machine state when that would lead to a different behaviour in the abstract machine.

In that sense I suppose it’s no different from things like removing a variable initialisation if the variable is never used. That also has a side effect in the abstract machine, but it can still be optimised out if that abstract machine side effect is not observable.