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by ZoomZoomZoom
350 days ago
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No problem, there's \b. echo "one two three four five" | awk '{$3="\b"; print}'
Inserts the backspace character (^H), which you can then remove with [global] substitution: awk '{$3="\b"; sub(/\32\b/, ""); print}'
You can, of course, use an arbitrary sentinel value for the field to be deleted. Should work in gawk and BWK awk. |
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