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by tikhonj
5049 days ago
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NaNs are annoying because, thanks to them, equality on floating point numbers is not an equivalence relation. In particular, NaN /= NaN. This means that in Haskell, for example, you cannot really rely on the Eq class representing an equivalence relation. Code relying on the fact that x == x should be true for all x could not work as expected for floating point numbers. I don't know if this has any practical ramifications in real code, but it certainly makes things less elegant and more complex than they have to be. |
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However, you should be able to examine two NaNs and declare them "equivalent" (for certain definitions of equivalence) by intelligently examining the bits based on the hardware that you're running the program on. In the case of a binary Nan [1] that would entail checking that the exponential fields are both entirely high (eg 0x8 == (a.exponent & b.exponent), assuming a standard 8 bit exponent) and that the mantissas are nonzero (eg a.mantissa && b.mantissa).
[1]: "Binary format NaNs are represented with the exponential field filled with ones (like infinity values), and some non-zero number in the significand (to make them distinct from infinity values)." --http://en.wikipedia.org/wiki/NaN