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by lblume
415 days ago
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> Secondly, why does this generate a uniform random number? Each interval of equal size occurs with equal likelihood at each step. Consider that you want to generate a random number between 0 and 1024 (excl.). The midpoint would be 512, thus you choose randomly whether the lower interval [0, 512) or the higher interval [512,1024) is selected. In each step, the range size is independent of the concrete numbers, i.e. for it is exactly 2^(-step_size) * (high - low), and in each step each range has equal probability. Thus if the algorithm terminates, the selected number was in fact uniformly sampled. I would also presume it must terminate. Assume that the two endpoints are one ulp apart. The midpoint is thus either of the two, there is no randomness involved (barring FPU flags but they don't count). In the next step, the algorithm either terminates or sets the endpoints equal, which also fixes the midpoint. Thus the procedure always returns the desired result. |
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