[tialaramex]

You can't really do Try (which is that operator's name in Rust) because C++ lacks a ControlFlow type which is how Try reflects the type's decision about whether to exit early.

You can imitate the beginner experience of the ? operator as magically handling trivial error cases by "just knowing" what should happen, but it's not the same thing as the current Try feature.

Barry Revzin has a proposal for some future C++ (lets say C++ 29) to introduce statement expressions, the syntax is very ugly even by C++ standards but it would semantically solve the problem you had.