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by kllrnohj
404 days ago
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You're requiring that packet #2 be available before packet #1 has finished. That's higher latency than the goal, which is packet #1 is processed & sent to output before packet #2 has arrived at all. Or perhaps you're missing that there's an in event as part of this, like a MIDI instrument? It's an in->effect->out sequence. So minimizing latency means that the "effect" part must be as small as possible, which means it's desired for it to happen faster than "in" can feed it data |
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