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by LeFantome
411 days ago
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The GPL has wrongly taught us to focus on “compatibility”. Compatibility is pretty much exclusively a copyleft issue. There is no reason that you cannot use this code with this license in a larger BSD work. It is “compatible” in that sense. This specific code has additional restrictions (not charging). That does not add any restrictions to the rest of the code though. So, if you are charging, you are in violation of the license just for this code snippet. Linus Torvalds, the copyright holder, could try to enforce the license against you. Since he gives it away, no financial damages. Which means the remedy would be that you would not be able to use this code anymore (but could still use the rest of BSD). I do not expect Linus to pursue enforcement on this one. It would be a very difficult case to win anyway as you would have to prove that people were being charged specifically for the Linus code and not for other code covered by BSD (which allows charging). I would argue that this license has not even been violated, unless somebody has put a price tag on this specific code. |
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