Hacker News new | ask | show | jobs
by kridsdale3 416 days ago
That's not true. If there are measurable performance differences.
2 comments

"strict" means something. People, including yourself, only care if there is a practical difference in performance. "this is lossless and that isn't lossless" is a completely useless statement in this realm. In many domains lossy compression is either not tolerated, not legal or not practical.
If you get any accuracy degradation with full 8 bits of precision you're doing it wrong.
Or your model wasn't trained so well (weights are too spiky)