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by dexen
5054 days ago
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> I think this is catastrophically broken because of a known issue of how SHA-2 breaks its input into blocks: when A is aligned to a block boundary, sha(A || B) = f(sha(A), g(B)). If that's the case, wouldn't it suffice to mix A and B, for example with byte-wise XOR? password ::= sha(A XOR B)
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