| And they must all be positive integers. So A + B = C and A + C = B. But we know that A + B = C, so we can replace C with (A + B). So we know that A + A + B = B. So 2A + B = B. Or 2A = 0. And this holds any way you slice it. Even if you were to try and brute force it. A = 1 B = 2 Then C = 3. But A + C has to equal B. That's 1 + 3 = 2? That's not true. I don't see a case where you can add to the sum of two numbers one of the numbers and get the other number. I'm guessing that's a misreading of the problem. Because it looks like the third number is the sum of the first two. |