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by madcaptenor 460 days ago
Looks like that's all of them. The typical number of even digits of n grows like a constant times n, so you need some very large deviations from t

I'd conjecture the number of powers of 2 with exactly m even digits is finite for all m.

1 comments

Just tested up to 2 * 1000000, and it indeed looks like that's all of them.
Asterisk means exponent here?
Yes. I didn't escape the asterisks before posting, and HN replaced ** with \* without me noticing.