Hacker News new | ask | show | jobs
by cco 464 days ago
> very first thing i think of when viewing their site is this is some lodging for volunteer/unpaid labour. https://www.workaway.info/

I'm certainly not an immigration lawyer but my understanding is that _no_ work, none, even in exchange for room and board, is allowed on a tourist visa in the US.

Workaway looks like it isn't compatible with a tourist visa in the US and their website doesn't really call that out. Seems like something that nine times out of ten if you're just quiet about it it'll never come up and you'd be fine.

But unfortunately Canada refused entry and then questions were asked. Rough.

3 comments

I wonder how Camp America is doing it these days.

https://www.campamerica.co.uk/the-experience/camp-jobs/campo...

Back in 1997 I participated. I had to get a J-1 visa, worked in a summer camp for about two months and got $400 pocket money. I entered the country using the program description, no deception.

Later I actually worked in the US - on a simple business trip visa - B1. For 12 months, interrupted by trips back home. Legally! Reentry got harder and harder with each return trip, and in the end I was taken to the back. But after explaining everything I git the stamp, no problem.

The secret: A big German company wanted to make the software of a big Silicon Valley company work on their platform. The obstacle: That company would not let their source code leave their premises. So this German job normally done in Germany had to be done on premise at the SV company. I still was a full German employee, only a temporary change of office because of that policy. It was acceptable for immigration. I don't think I would try that kind of thing again these days though.

“Generally you will be expected to help around 5 hours per day in exchange for food and accommodation. Some hosts may give a paid allowance to ensure they are offering at least the minimum wage in their country.”
That doesn’t make it legal, particularly in the US
The hint is in the name itself.