One divided by zero is a singularity. Singularity, mathematically speaking, means your math breaks. Calculus gets around this problem with limits. But there is absolutely nothing about physics that prohibits singularities, even gravitational singularities, in a zero G space because by definition a gravitational singularity per se has an undefined G.
If they don’t doesn’t that imply that a superextremal black hole could exist since there would be no naked singularity whose observation is forbidden by any cosmic censorship hypothesis?
> Singularity means that at least some barions will be at the same place in the same time
The singularity in a black hole has no conception of baryons, hadrons or fermions. Those are quantum particles. The singularity is in general relativity.
Also, 0G doesn’t mean zero gravity. An object in freefall is still subject to gravity despite experiencing 0G.
(Side note: fermions can occupy the same place at the same time. They cannot occupy the same state. This seeming mathematic fuckery goes on to describe many real-world weirdos like neutron stars.)
If matter falling into a singularity never reaches it because time slows down infinitely as you approach, wouldn’t this be a physical representation of a mathematical limit from calculus? The actual literal 1d singularity never forms but it is approached infinitely close.