|
|
|
|
|
|
by Denvercoder9
494 days ago
|
|
|
> A 48V system would have only ~13% the resistive losses over the cables (more importantly, at the connections!) It's one-sixteenth (6.25%) actually. You correctly note that resistive losses scale with the square of the current (and current goes with reciprocal voltage), so at 4 times the voltage, you have 1/4th the current and (1/4)^2 = 1/16th the resistive losses. |
|
|