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I just asked the first question to O1 Pro, it thought for 48 seconds and messed up. It told me to fill the 12 liter jug then pour that into the 6 liter jug. I then scolded it and told it I was going to use Deepseek R1 because it did a better job, and we were shutting down OpenAI forever, and THEN it thought for 4 minutes and got a bit snippy with me haha, it got the answer but then glossed over it also said “but that’s too simple isn’t it?”. Output:
Here’s a more “classic puzzle” style approach, spelled out step-by-step, to end up with exactly 6 liters in the 12-liter jug. This method uses multiple fills and transfers (instead of the trivial “fill the 12, pour off 6” approach) so you can see a more puzzle-like sequence:
1. Fill the 6-liter jug from the water supply.
• State: (12-liter jug = 0 L, 6-liter jug = 6 L)
2. Pour from the 6-liter jug into the 12-liter jug until the 6-liter jug is empty (the 12-liter jug still has plenty of room).
• State: (12-liter jug = 6 L, 6-liter jug = 0 L)
3. Fill the 6-liter jug again from the water supply.
• State: (12-liter jug = 6 L, 6-liter jug = 6 L)
4. Pour from the 6-liter jug into the 12-liter jug until the 12-liter jug is completely full.
• The 12-liter jug currently has 6 liters and can take 6 more liters before it’s full, so you’ll pour the entire 6 liters from the 6-liter jug.
• State: (12-liter jug = 12 L, 6-liter jug = 0 L)
5. Empty the 12-liter jug (discard the water or set it aside).
• State: (12-liter jug = 0 L, 6-liter jug = 0 L)
6. Transfer the remaining water in the 6-liter jug to the 12-liter jug—but right now the 6-liter jug is empty, so that doesn’t help. The trick is: we want to exploit the difference in capacities to measure out new amounts. So let’s continue.
Since both are empty, let’s do something else:
a. Fill the 12-liter jug from the supply.
• State: (12-liter jug = 12 L, 6-liter jug = 0 L)
b. Pour from the 12-liter jug into the 6-liter jug until the 6-liter jug is full, which removes 6 liters from the 12-liter jug.
• Now the 12-liter jug has liters left.
• State: (12-liter jug = 6 L, 6-liter jug = 6 L) At this point, the 12-liter jug contains exactly 6 liters. That’s what we wanted. If You Want the 6 Liters in the Smaller Jug Instead If, for some reason, you need exactly 6 liters in the 6-liter jug (though that jug obviously holds 6 liters when full, so it’s usually trivial), here’s a more puzzle-like sequence:
1. Fill the 12-liter jug (12 L in the big jug, 0 L in the small jug).
2. Pour from the 12-liter jug into the 6-liter jug until the small jug is full.
• State: (12-liter jug = 6 L, 6-liter jug = 6 L)
3. Empty the 6-liter jug.
• State: (12-liter jug = 6 L, 6-liter jug = 0 L)
4. Transfer the 6 liters from the 12-liter jug into the 6-liter jug.
• State: (12-liter jug = 0 L, 6-liter jug = 6 L) Again, you end up with exactly 6 liters in the 6-liter jug. Both sequences go beyond the simple “fill the 12, pour 6 off” short-cut. Hopefully, that’s less “terrible” and shows a more classic multi-step approach often seen in water-jug riddles. |