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by hansvm
493 days ago
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> valid, 128 bits The birthday paradox is a thing. If you have 128 bits of entropy, you expect the 50% mark to be proportional to 64-bit keys, not 128 bits. 64 bits is a lot, but in my current $WORK project if I only had 128 bits of entropy the chance of failure any given year would be 0.16%. That's not a lot, but it's not a negligible amount either. Bigger companies care more. Google has a paper floating around about how "64 bits isn't as big as it used to be" or something to that effect, complaining about how they're running out of 64-bit keys and can't blindly use 128-bit random keys to prevent duplication. > bits of entropy Consumer-grade hash functions are often the wrong place to look for best-case collision chances. Take, e.g., the default Python hash function which hashes each integer to itself (mod 2^64). The collision chance for truly random data is sufficiently low, but every big dictionary I've seen in a real-world Python project has had a few collisions. Other languages usually make similar tradeoffs (almost nobody uses crytographic hashes by default since they're too slow). I wouldn't, by default, trust a generic 1-million-bit hash to not have collisions in a program of any size and complexity. 128 bits, even with low enough execution counts to otherwise make sense, is also unlikely to pan out in the real world. |
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Birthday paradox applies when you store the items together (it's a chance of collision against any existing item in the set), so overall annual hashing churn isn't affected (more hashes against a smaller set doesn't increase your collision probability as quickly).