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by michael1999
514 days ago
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You are correct. I thinko'd and missed the edit window. I meant to say: Math usually considers (-7 mod 5) === (3 mod 5). But in C, (-7 % 5 != 3 % 5). The issue is that -7 and 3 are congruent, but the % operator keeps the sign. So -7 % 5 yields -2, not +3. Those are congruent, but not equal. I've never had a use for this behaviour, but I've definitely had to work around it. The lazy way is ((x % n) + n) % n which is safe (assuming n > 0). |
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