Hacker News new | ask | show | jobs
by rak1507 546 days ago
What do you mean by x^x^x^... = 2? Isn't the solution to that sqrt(2)?
1 comments
77pt77 546 days ago
f(x,n) = f(x,n-1) ^ x

f(x,1) = x

c_n is such that f(c_n,n) = 2

c = lim c_n

link
rak1507 546 days ago
Do you mean f(x,n-1)^x or x^f(x,n-1)? With the first definition, c=1, the second, c=sqrt(2). I'm still not seeing the connection to omega.
link