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by berikv 542 days ago
Correcting the correction:

> When you connect 2 9000 mAh cells in series, the resulting battery has 2x the voltage but the same mAh capacity. In parallel, the battery has the same voltage but 2x the mAh.

The relevant units are:

* Capacity (Q, in mAh, Ah, kWh, etc)

* Power (P, in Watts)

* Voltage (U, in Volts)

* Current (I, in Amperes)

* Duration (t, in mostly measured in hours)

And the relevant formulas are:

* P = U x I or Power equals Voltage(difference) times Current

* Q = P x t or Capacity equals Power times duration

From this we can establish that connecting batteries in series or in parallel will not change their Capacity. When having 13 batteries of 29000mAh, or 29Ah, you have 13 x 29 = 377Ah or 377000mAh. Connecting batteries in series or parallel does make a difference in voltage and current: a string in series will increase the voltage while keeping the current the same (theoretically, in practice you get less than the current of the weakest cell); a parallel setup will increase the maximum current while keeping the voltage the same (again, in theory).

1 comments

If you have two 1000 mAh cells connected in series, they will provide 1 amp for 1 hour. The battery is still 1000 mAh even though it is made of two cells with 2000 mAh total.

You are equating amp-hours with watt-hours, which is not reasonable. Q is charge, and is only proportional to a number of electrons. E is the energy, or a number of electrons at a voltage.

> When having 13 batteries of 29000mAh, or 29Ah, you have 13 x 29 = 377Ah or 377000mAh

By this logic, with those cells in series the whole battery would be at 48 volts and 337 amp-hours, giving it a storage of 18.1 kWh. That's despite being made of 13 cells with only 107 watt-hours each.