[GrantMoyer]

In the case of the example, there is a move, and std::move works in the example.

The function, show, doesn't take a copy, it takes a Person object. Persons can be copy constructed or move constructed (both constructors are implicit, since there's no user-defined constructors). std::move returns an r-value reference to main's p, so Person's implicit move constructor is called, and show's p argument is move constructed from main's p. The reported address changes because moving creates a new object in C++, but the moved-to object may take ownership of the heap allocated memory and other resources from the moved-from object.

In this case, the moved-to Person takes ownership of the heap allocation from the moved-from Person's string member and sets the moved-from Person's string member to an empty string. Without std::move, show's p is copy constructed, including its string member.